1 if limn > +oo {N(n) \over A(n)} = 0 or = +oo. A(n) is a "regular threshold function" of A if there exists a probability distribution function F(x) such that limn > +oo Pn,N(n)(A) = F(x) if limn > +oo {N(n) \over A(n)} = x, where 0 < x <+oo and x is a point of continuity of F(x). The investigated properties are as follows: the presence of certain subgraphs (e. g. trees, complete subgraphs, cycles, etc.) or connectedness, number of components etc. The results are of the following type: Theorem 3a. Suppose that N(n) ~ cn, where c > 0. Let \gammak denote the number of cycles of order k contained in \Gamman,N (k = 3,4,...). Then we have limn > +oo Pn,N(n) (\gammak = j) = \lambdaj e-\lambda/j!, where j = 0,1,... and \lambda = (2c)k/2k. Thus the threshold distribution corresponding to the threshold function A(n) = n for the property that the graph contains a cycle of order k is 1-e-(2c)k/2k.
Reviewer: K.Culik
Classif.: * 05C80 Random graphs
Index Words: topology
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