Equation Icon  [(j1'+ j3;2') + (j1 + j2;3);22'] = [D2'D2D3D3' - I]f1, (53) [(j + j ' ) + (j '+ j ') '] = [D D 'D 'D - I]f . (54) 1 2 ;3 1 3;2 ;33 3 3 2 2 1